首页> 外文OA文献 >Often harder than in the Constructive Case: Destructive Bribery in CP-nets
【2h】

Often harder than in the Constructive Case: Destructive Bribery in CP-nets

机译:通常比建设性案例更难:破坏性贿赂   Cp-网

代理获取
本网站仅为用户提供外文OA文献查询和代理获取服务,本网站没有原文。下单后我们将采用程序或人工为您竭诚获取高质量的原文,但由于OA文献来源多样且变更频繁,仍可能出现获取不到、文献不完整或与标题不符等情况,如果获取不到我们将提供退款服务。请知悉。

摘要

We study the complexity of the destructive bribery problem---an externalagent tries to prevent a disliked candidate from winning by briberyactions---in voting over combinatorial domains, where the set of candidates isthe Cartesian product of several issues. This problem is related to the conceptof the margin of victory of an election which constitutes a measure ofrobustness of the election outcome and plays an important role in the contextof electronic voting. In our setting, voters have conditional preferences overassignments to these issues, modelled by CP-nets. We settle the complexity ofall combinations of this problem based on distinctions of four voting rules,five cost schemes, three bribery actions, weighted and unweighted voters, aswell as the negative and the non-negative scenario. We show that almost all ofthese cases are NP-complete or NP-hard for weighted votes while approximatelyhalf of the cases can be solved in polynomial time for unweighted votes.
机译:我们研究了破坏性贿赂问题的复杂性-外在代理试图通过贿赂行为阻止不受欢迎的候选人赢得贿赂-在组合域投票中,其中候选者集合是若干问题的笛卡尔积。这个问题与选举获胜幅度的概念有关,该概念构成了选举结果的鲁棒性的度量,并且在电子投票的背景下起着重要作用。在我们的情况下,选民对CP-net所模拟的问题有条件优先分配。我们基于四个投票规则,五个成本计划,三个贿赂行为,加权和未加权选民以及否定和非否定情况的区别,解决了此问题所有组合的复杂性。我们证明,对于加权投票,几乎所有这些案例都是NP完全或NP困难的,而对于加权加权,大约一半的案例可以在多项式时间内求解。

著录项

相似文献

  • 外文文献
  • 中文文献
  • 专利
代理获取

客服邮箱:kefu@zhangqiaokeyan.com

京公网安备:11010802029741号 ICP备案号:京ICP备15016152号-6 六维联合信息科技 (北京) 有限公司©版权所有
  • 客服微信

  • 服务号